G12+john,+ando,+chris

Mass of an object A 0.160kg mass of an object B 0.257kg

Table 1; finding the momentum (s) ||||= Speed (m/s) ||||= Momentum (k*m/s) ||
 * ~  ||||= Distance (m) ||= Time before collision
 * ~  ||= A ||= B ||=   ||= A ||= B ||= A ||= B ||
 * = Trial 1 ||= 0.60 ||= 0.20 ||= 2'87'' ||= 0.209 ||= 0.0697 ||= 0.0334 ||= 0.0179 ||
 * = Trial 2 ||= 0.50 ||= 0.30 ||= 6'79'' ||= 0.0736 ||= 0.0442 ||= 0.0118 ||= 0.0114 ||

Table 2; comparing the momentum between before collision and after collision
 * ~  ||||= Distance (m) ||= Time before collision (s) ||||= Speed before collision (m/s) ||||= Time after collision (s) ||||= Speed after collision (m/s) ||||= Momentum of before collision (k*m/s) ||||= Momentum of after collision (k*m/s) ||
 * ~  ||= A ||= B ||=   ||= A ||= B ||= A ||= B ||= A ||= B ||= A ||= B ||= A ||= B ||
 * = Trial 1 ||= 0.43 ||= 0.37 ||= 1'99 ||= 0.216 ||= 0.186 ||= 1'35 ||= 2'79'' ||= 0.319 ||= 0.133 ||= 0.0346 ||= 0.0479 ||= 0.0510 ||= 0.0342 ||
 * = Trial 2 ||= 0.57 ||= 0.23 ||= 1'20 ||= 0.475 ||= 0.192 ||= 1'77 ||= 0'92'' ||= 0.322 ||= 0.250 ||= 0.0760 ||= 0.0493 ||= 0.05150 ||= 0.06425 ||

Identifying the accuracy of the conserved momentum based on the results from Table 2; Trial 1 Total momentum before collision 0.0346 + 0.0479 = 0.0825 Total momentum after collision 0.0510 + 0.0342 = 0.0852

96.831% accurate Trial 2 Total momentum before collision 0.0760 + 0.0493 = 0.1253 Total momentum after collision 0.05150 + 0.06425 = 0.11575

92.378% accurate

Conclusion; Above results show that the momentum is conserved.


 * here is a one cell || 90 degrees || 60 degrees || 30 degress ||
 * one mass ||  ||   ||   ||
 * two mass ||  ||   ||   ||
 * three mass ||  ||   ||   ||